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r^2-31r+30=0
a = 1; b = -31; c = +30;
Δ = b2-4ac
Δ = -312-4·1·30
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-29}{2*1}=\frac{2}{2} =1 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+29}{2*1}=\frac{60}{2} =30 $
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